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of the module:
a) The main series winding is connected to terminals 3 and 4.
b) The compensating winding is connected to terminals 5 and 6.
c) The brushes (commutator and armature winding) are connected to terminals 1 and 2.
10.
c) Measure and record the line current.
I ≅ 1.2 Aac
14.
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Chapter 5. DC Motor Modeling in the Inverted Pendulum and Its Step Response
1.OBJECT
- Understand the transient response and the steady-state response.
- Understand the procedure for modeling the motor of an inverted pendulum system and understand its mathematical representation.
- Compare s
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Chapter 7. Lead Compensator Design
1.OBJECT
- Learn how to design a lead compensator based on the root locus theory.
- Observe the change of the lead compensator applied to the inverted pendulum motor.
- Carry out the position control of the inverted pendulum motor by using a lead compensato
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이용해 다시 중진공 상태로 만든다. 그 후 CRYO펌프를 이용해 고진공 상태로 내린다.
⑨pre sputtering - 챔버내의 온도를 200℃로 1.실험목적
2.기초이론 및 원리
3.준비 기구 및 장치
4.실험과정
5.실험결과
6.토의 및 고찰
7.인용 및 참고문헌
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1.Heat Capacity of Gas
2.Vapor pressure of a pure liquid
3.
4.
5.
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1020m-3보다 큰 농도의 경우, 양쪽 그림의 곡선들이 도펀트 농도가 증가함에 따라 점진적으로 낮은 이동도 값으로 이동하는 것을 볼 수 있다. 1.실험제목
2.실험목적
3.이론
(1)금속의 전기전도도
-온도의 영향
-불순물의 영형
-전기전
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10 processes from creating channels in Wafer to producing them with PDMS casting. First of all, it goes through 7 processes to create channels in the wager. Spin coating (two different rotations) the wafer with the Su-8 photoresist. The process of soft baking is performed according to the thickness
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11059200UL
int main()
{
unsigned int i;
DDRD = 0xff;
PORTD = 0x01;
while(1){
for(i=0;i<8;i++)
{
_delay_ms(200);
PORTD = PORTD << 1;
}
PORTD = 0x10;
for(i=0;i<8;i++)
{
_delay_ms(400);
PORTD = PORTD >> 1;
}
PORTD = 0x01;
}
return 0;
}
B.Data
C.Discussion
It is an application of ex1,
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12900
(H2N)C6H4SO3H
(Sulfanilic acid)
1.00
0.78
4600
3588
C6H5N(CH3)2
(Dimethyl aniline)
0.70
0.55
2300
1265
C14H14N3NaO3S
(Methyl Orange)
1.28
1
160000
5) 재물조사
파손 및 분실 기기명
갯수
금액(원)
파손 및 분실 경위
-
-
-
-
6) 안전사고
사고자
상처 부위 및 크기
처치 결과
사
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of errors.
① The mol fraction is very sensitive. So there are numerical errors. As we round off the value, fraction can be changed greatly. So It depends on how we solve the material balance. Actually, The weight is changed in rage of 1g, the mol fraction is changed in rage of 10%. Although we use t
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